Frequently Asked Questions...
A 100 W lightbulb generates 95 W of heat, which is dissipated through a?
A 100 W lightbulb generates 95 W of heat, which is dissipated through a glass bulb that has a radius of 3.2 cm and is 0.8 mm thick. What is the difference in temperature between the inner and outer surfaces of the glass?
C°
please help// explann and give correct answer..please.. im desperate
Answer:
My heat transfer is a bit rusty but I believe you would need to know the thermal coeffiecent of the glass and also the thickness...
So the heat transfer is like this...
T(fillament) ~~ T(inert gas) ~~ T(glass inner) ~~ T(glass outer)
The 95W you are given is your Q value.
You must find your resistance of glass using that thermal coefficent (k).
The end equation looks like this:
Q= [(Tinternal air - Texternal)/((1/h*A)internal + 1/(k*S)glass + (1/h*A)external)
So you know every thing but Tinternal - Texternal which is what you want AKA delta T or difference in T.
Unfortunatly I do not remember exactly how to find convective resistances. 'h' I believe is usually given.
Hope that helps!
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